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1. Your Microsoft MapPoint Web Service (MWS) User Id is 124566, and your MWS password is P@ssw0rd. You need to use MWS to create an application. Which code segment should you use?
A) System.Net.NetworkCredential appCredential = new
System.Net.NetworkCredential("124566", "P@ssw0rd");
B) System.Security.Principal.GenericIdentity appCredential = new
System.Security.Principal.GenericIdentity ("124566", "P@ssw0rd");
C) System.Security.Principal.NTAccount appCredential = new
System.Security.Principal.NTAccount("124566", "P@ssw0rd");
D) System.EnterpriseServices.SecurityIdentity appCredential = new
System.EnterpriseServices.SecurityIdentity ("124566", "P@ssw0rd");
2. You are creating a Web application by using the Virtual Earth 6.0 map control.
A Web page of the application provides links to a number of pre-defined locations. The application must meet the following requirements:
The links can be shared.
The links are encoded with map properties.
Users can copy the links to the Windows clipboard.
You need to write code to meet the requirements.
Which code fragment should you use?
A) <a id="Link" href="http: //www.mymappingsite.com/mymappage.aspx?40.689167&-
74.04472&16&h">Liberty</a>
B) <code id="Link"
onclick="window.open(location.protocol+location.pathname+'?40.689167&-
7 4.04472&16&h');"> Liberty </code>
C) <address id="Link"
onclick="location.replace(location.protocol+location.pathname+'?40.689167&-
74.04472&16&h');"> Liberty </address>
D) <button id="Link" onclick="location.replace(' http:
//www.mymappingsite.com/mymappage.aspx?40.689167&-74.04472&16&h');"> Liberty
< /button>
3. You create a Microsoft MapPoint Web Service application that accepts routes from users.
You need to find points of interest that are within one mile of a route or within three miles of the endpoints of the route. What are two possible ways to achieve the goal? (Each correct answer presents a complete solution. Choose two.)
A) findNearRouteSpec.Distance = 1; findResults =
findService.FindNearRoute(findNearRouteSpec); foundLocations.Add(findResults); findNearbySpec.Distance = 3; foreach (Segment segment in route.Itinerary.Segments) { findNearbySpec.LatLong = segment.Waypoint.Location.LatLong; findResults = findService.FindNearby(findNearbySpec); foundLocations.Add(findResults); }
B) findNearRouteSpec.Distance = 1; findResults =
findService.FindNearRoute(findNearRouteSpec); foundLocations.Add(findResults); findNearbySpec.Distance = 3; findNearbySpec.LatLong = startLatLong; findResults = findService.FindNearby(findNearbySpec); foundLocations.Add(findResults); findNearbySpec.LatLong = endLatLong; findResults =
findService.FindNearby(findNearbySpec); foundLocations.Add(findResults);
C) findNearRouteSpec.Distance = 1; findResults =
findService.FindNearRoute(findNearRouteSpec); foundLocations.Add(findResults); findNearbySpec.Distance = 3; foreach (FindResult findResult in findResults.Results) { findNearbySpec.LatLong = findResult.FoundLocation.LatLong; findResults = findService.FindNearby(findNearbySpec); foundLocations.Add(findResults); }
D) findNearRouteSpec.Distance = 1; findResults =
findService.FindNearRoute(findNearRouteSpec); foundLocations.Add(findResults); findNearbySpec.Distance = 3; foreach (Segment segment in route.Itinerary.Segments) { foreach (Direction direction in segment.Directions) { findNearbySpec.LatLong = direction.LatLong; findResults = findService.FindNearby(findNearbySpec); foundLocations.Add(findResults); } }
4. You need to hide the compass and the zoom control on a two-dimensional Virtual Earth 6.0 map. What are two possible ways to achieve this goal? (Each correct answer presents a complete solution. Choose two.)
A) Hide the default dashboard.
B) Hide the navigation control for the globe.
C) Set the value of the fixed parameter of the VEMap.LoadMap method to true.
D) Clear the map by using the VEMap.Clear method.
5. You are integrating third-party data into a Virtual Earth 6.0 application. The data that is retrieved from the third party is stored in an array named Results. The Results array is stored inside a Web handler. The data is stored in the following format.
R esults[0]["name"] = "A. Datum Corporation";
Results[0]["address"] = " 123 Main St. , New York , NY ";
Results[0]["latitude"] = "40.123";
Results[0]["longitude"] = "-70.456";
Results[0]["thumbnail"] = "http://www.adatum.com/st3465.jpg";
...
Results[x]
The Web handler uses the GeoRSSFeed class to accept items of type GeoRSSItem. The class contains the ToString() method that writes the GeoRSS feed to a string.
The Web handler GeoRSS integration is defined by the following code segment. (Line numbers are included for reference only.)
0 1 GeoRSSFeed feed = new GeoRSSFeed();
0 2 GeoRSSItem curItem;
0 3 for (int i = 0; i < Results.length; i++){
0 4 curItem = new GeoRSSItem();
0 5 ...
0 6 feed.Add(curItem);
0 7 }
0 8 // Write feed to HTTP Response
0 9 context.Write(feed.ToString());
The Web handler uses the GeoRSSItem class that contains the following code segment.
(Line numbers are included for reference only.)
1 0 public class GeoRSSItem {
1 1 public Dictionary < string, string > elements;
1 2 publ ic GeoRSSItem(){
1 3 elements = Dictionary < string, string > ();
1 4 }
1 5 public void Add(string pName, string pValue){
1 6 elements.Add(pName, pValue);
1 7 }
1 8 }
You need to encode the data inside the Results array into the GeoRSS format.
Which code segment should you insert at line 05?
A) String [] keys = Results[i].Keys; String curKey; For (int i = 0; i < keys.length; i++){ curKey = keys[i]; curItem.Add(curKey, Results[i][curKey]); }
B) curItem.Add("title", Results[i]["name"]); curItem.Add("description", string.Format("{0}|{1}",
_ Results[i]["address"], _ Results[i]["thumbnail"]); curItem.Add("latitude",
Results[i]["latitude"]); cur Item.Add("longitude", Results[i]["longitude"]);
C) curItem.Add("name", Results[i]["name"]);
curItem.Add("address", string.Format("{0}|{1}", _
Results[i]["address"], _
Results[i]["thumbnail"]);
curItem.Add("latitude", Results[i]["latitude"]);
curItem.Add("longitude", Results[i]["longitude"]);
D) curItem.Add("title", Results[i]["name"]); curItem.Add("description", Results[i]["address"]); curItem.Add("latitude", Results[i]["latitude"]); curItem.Add("longitude",
Results[i]["longitude"]); curItem.Add("icon", Results[i]["thumbnail"]);
Solutions:
| Question # 1 Answer: A | Question # 2 Answer: A | Question # 3 Answer: A,B | Question # 4 Answer: A,C | Question # 5 Answer: B |
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